(a) Find F top , the magnitude of the totaldownward force on the top of the cube
ID: 1673392 • Letter: #
Question
(a) Find Ftop, the magnitude of the totaldownward force on the top of the cube from the liquid and theatmosphere, assuming atmospheric pressure is 1.00 atm.N
(b) Find Fbottom, the magnitude of thetotal upward force on the bottom of the cube.
N
(c) Find T, the tension in the rope.
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(d) Calculate Fbu, the magnitude of thebuoyant force on the cube using Archimedes' principle.
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What relation exists among all these quantities? (Select all thatapply.) Fbu = Ftop - FbottomFbu = Fbottom + TFbu = m - TFbu = Fbottom - FtopFbu = T - m
Fbu = Ftop - FbottomFbu = Fbottom + TFbu = m - TFbu = Fbottom - FtopFbu = T - m
Fbu = Ftop - FbottomFbu = Fbottom + TFbu = m - TFbu = Fbottom - FtopFbu = T - m
In the figure below, a cube of edgelength L = 0.650 m and mass 520 kg is suspended by a rope in an open tank ofliquid of density 1030 kg/m3. (a) Find Ftop, the magnitude of the totaldownward force on the top of the cube from the liquid and theatmosphere, assuming atmospheric pressure is 1.00 atm. N (b) Find Fbottom, the magnitude of thetotal upward force on the bottom of the cube. N (c) Find T, the tension in the rope. N (d) Calculate Fbu, the magnitude of thebuoyant force on the cube using Archimedes' principle. N What relation exists among all these quantities? (Select all thatapply.) Fbu = Ftop - Fbottom Fbu = Fbottom + T Fbu = m - T Fbu = Fbottom - Ftop Fbu = T - m
Explanation / Answer
Ftop, the magnitude of the total downwardforce on the top of the cube from the liquid and the atmosphere,assuming atmospheric pressure is 1.00 atm. 1 atm=105 Pa Ftop=(105 +L/2*1030*9.8)*L2=43.64*103 N (b)bottom, the magnitude of the total upward forceon the bottom of the cube Fbottom==(105+L*3/2*1030*9.8)*L2=46.41*103 N (c)T, the tension in the rope. T=-(Fbottom -Ftop)+ weight of the cube=2328 N (d) Fbu, the magnitude of the buoyantforce on the cube using Archimedes' principle F=1030*9.8*L3=2772 N (e)Fbu=Fbottom-FtopRelated Questions
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