Question part Points Submissions 1 2 0/5 0/5 0/10 0/10 Total 0/10 Vector A point
ID: 1673650 • Letter: Q
Question
Question part Points Submissions 1 2 0/5 0/5 0/10 0/10 Total 0/10 Vector A points 43° counterclockwisefrom the x axis. Vector B is twice as long as A.Their product A×B has length A2 andpoints in the negative z direction. What is the directionof vector B? (Measure from the positive x axis with thecounterclockwise direction positive.) Question part Points Submissions 1 2 0/5 0/5 0/10 0/10 Total 0/10 Question part Points Submissions 1 2 0/5 0/5 0/10 0/10 Total 0/10 Question part Points Submissions 1 2 0/5 0/5 0/10 0/10 Total 0/10 Question part Points Submissions Question part Points Submissions 1 2 0/5 0/5 0/10 0/10 Total 0/10 Total 0/10 Vector A points 43° counterclockwisefrom the x axis. Vector B is twice as long as A.Their product A×B has length A2 andpoints in the negative z direction. What is the directionof vector B? (Measure from the positive x axis with thecounterclockwise direction positive.) Vector A points 43° counterclockwisefrom the x axis. Vector B is twice as long as A.Their product A×B has length A2 andpoints in the negative z direction. What is the directionof vector B? (Measure from the positive x axis with thecounterclockwise direction positive.) 1 2 0/5 0/5 0/10 0/10Explanation / Answer
from the problem find the angle between thevectors A x B = A Bsin A2 = A * 2A sin 1/2 = sin = 30 0 or 150 0 the angle between A and B, so it looks like this: A is 43 deg from the x axis, so B couldbe 43 - 30 = 130 from the x axis B could be 43 - 150 = -1070 from the xaxisRelated Questions
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