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Question part Points Submissions 1 2 0/5 0/5 0/10 0/10 Total 0/10 Vector A point

ID: 1673650 • Letter: Q

Question

Question part Points Submissions 1 2 0/5 0/5 0/10 0/10 Total 0/10 Vector A points 43° counterclockwisefrom the x axis. Vector B is twice as long as A.Their product A×B has length A2 andpoints in the negative z direction. What is the directionof vector B? (Measure from the positive x axis with thecounterclockwise direction positive.) Question part Points Submissions 1 2 0/5 0/5 0/10 0/10 Total 0/10 Question part Points Submissions 1 2 0/5 0/5 0/10 0/10 Total 0/10 Question part Points Submissions 1 2 0/5 0/5 0/10 0/10 Total 0/10 Question part Points Submissions Question part Points Submissions 1 2 0/5 0/5 0/10 0/10 Total 0/10 Total 0/10 Vector A points 43° counterclockwisefrom the x axis. Vector B is twice as long as A.Their product A×B has length A2 andpoints in the negative z direction. What is the directionof vector B? (Measure from the positive x axis with thecounterclockwise direction positive.) Vector A points 43° counterclockwisefrom the x axis. Vector B is twice as long as A.Their product A×B has length A2 andpoints in the negative z direction. What is the directionof vector B? (Measure from the positive x axis with thecounterclockwise direction positive.) 1 2 0/5 0/5 0/10 0/10

Explanation / Answer

from the problem find the angle between thevectors        A x B = A Bsin         A2 = A * 2A sin         1/2 = sin            = 30 0   or   150 0 the angle between A and B, so it looks like this:                 A is   43 deg from the x axis, so B couldbe      43 - 30 = 130 from the x axis                                                                                   B could be   43 - 150  =  -1070 from the xaxis
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