a .50kg ball tied to the end of a 1.3m light cord is revolvedin a horizontal pla

Question

a .50kg ball tied to the end of a 1.3m light cord is revolvedin a horizontal plane with the cord making a 30 degree angle withthe vertical A) wha tis the balls speed B)if the ball is revolved so the speed is 4m/s what angle doesthe cord need to be at the vertical C)if the cord withstands a max tension of 9.8N whats the maxspeed the ball can move a .50kg ball tied to the end of a 1.3m light cord is revolvedin a horizontal plane with the cord making a 30 degree angle withthe vertical A) wha tis the balls speed B)if the ball is revolved so the speed is 4m/s what angle doesthe cord need to be at the vertical C)if the cord withstands a max tension of 9.8N whats the maxspeed the ball can move

Explanation / Answer

The equation of motion of the ball are         T cos = mg And T sin = mV^2 / R   From the above equations the speed ofhte ballis         V = Lgtan sin            = [(1.3)(9.8)sin30 tan30             = 1.917m/s. b) angle made is          =tan^-1 ( V^2 / Rg )    Here R = L sin c) maximum tension that it can with stand is          T sin = mV^2 / R          T = mV^2 / R sin PLug in values.

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