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An airplane with a speed of 76 m/s is climbing upward at an angleof 44° with res

ID: 1673890 • Letter: A

Question

An airplane with a speed of 76 m/s is climbing upward at an angleof 44° with respect tothe horizontal. When the plane's altitude is 500 m, the pilot releases apackage.
(a) Calculate the distance along the ground, measured from a pointdirectly beneath the point of release, to where the package hitsthe earth.
m

(b) Relative to the ground determine the angle of the velocityvector of the package just before impact.
°clockwise from the positive x axis (a) Calculate the distance along the ground, measured from a pointdirectly beneath the point of release, to where the package hitsthe earth.
m

(b) Relative to the ground determine the angle of the velocityvector of the package just before impact.
°clockwise from the positive x axis

Explanation / Answer

Speed of airplane v = 76 m/s Angle = 44 o Altitude of plane H = 500 m Horizontal velocity of the plane u = v cos                                                  = 54.669 m/s (a). Required distance = u [2H/g]                                  = 552.24 m
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