In a location where the speed of sound is 337 m/s, a 2000 Hz sound wave impinges
ID: 1673933 • Letter: I
Question
In a location where the speed of sound is 337 m/s, a 2000 Hz sound wave impinges on two slits 30cm apart. (a) At what angle is the first maximumlocated?1°
(b) If the sound wave is replaced by 3.00cm microwaves, what slit separation gives the same angle for thefirst maximum?
2 cm
(c) If the slit separation is 1.00 µm, what frequency lightgives the same first maximum angle?
3 THz (a) At what angle is the first maximumlocated?
1°
(b) If the sound wave is replaced by 3.00cm microwaves, what slit separation gives the same angle for thefirst maximum?
2 cm
(c) If the slit separation is 1.00 µm, what frequency lightgives the same first maximum angle?
3 THz
Explanation / Answer
Speed of sound v = 337m/s frequency of sound f =2000Hz So that the wave length is= v /f = 337 / 2000 = 0.1685m
distance between the slits d =3.0cm The path difference = d Sinm
where m is the angle for the mth fringe. a) The condition for maximumis path difference = m 0r d Sin m =m for the firstorder m = 1 ,
Therefore 1=Sin-1( / d )
= sin-1 ( 0.1685 / 0.3)
=34.17o
b) Here = ' =3cm therefore thewidth of the slit d ' = ' / Sin1 = 0.03 / sin34.17
= 0.0534 m
= 5.34 cm
c) All factors remaining the samed = d ' = 1*10-6m Thewavelength of light ' = d ' Sin1
= 0.0534 * sin34.17
= 0.0299 m
Hence thefrequency of light f = c / '
= 3 x 108 / 0.0299
= 1 x 1010 Hz
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