A fortune teller\'s glass ball is 10 cm in diameter. Her secretring is placed 6

Question

A fortune teller's glass ball is 10 cm in diameter. Her secretring is placed 6 m from the edge of the ball. a. An image of the ring appears on the opposite side of theglass ball. how far is the image from the centerof the ball? b. the crystal ball is removed and a thin lens is placed wherethe center of the ball had been. if the image is still in the sameposition , what is the focal length of the lens? A fortune teller's glass ball is 10 cm in diameter. Her secretring is placed 6 m from the edge of the ball. a. An image of the ring appears on the opposite side of theglass ball. how far is the image from the centerof the ball? b. the crystal ball is removed and a thin lens is placed wherethe center of the ball had been. if the image is still in the sameposition , what is the focal length of the lens?

Explanation / Answer

Lol. I guess you are in my class...Burko? I may be wrong, but here's what I'm doing: Part a) using n1/p + n2/i = (n2-n1)/r solve for i. Assume refractive index of n1 = 1 and n2 = 1.5(glass) then using f = [n2d / 4 (n2-1)] - d/2 solve for f (i pulled this fromhttp://www.edmundoptics.com/technical-support/optics/understanding-ball-lenses/) now you know the f length from the edge of the ball. You can try now to draw a ray trace through the sphere, using theprinciples for ray tracing found in 34-7. Part b) Since the P and I are the same, use: 1/p + 1/i = 1/f to find new focal length for a thin lens.

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