Researchers in northern Saskatchewan recently found a small group of woodland ca

Question

Researchers in northern Saskatchewan recently found a small group of woodland caribou that appeared to be isolated from other caribou herds. Several calves in this herd showed bone abnormalities The researchers are concerned that the abnormalities are due to an unusual level of inbreeding They genotyped all 24 caribou and found these results for two alleles at one locus: homozygous for A_1 = 8 caribou, heterozygous A_1 A_2= 10 caribou, homozygous for A_2 = 6 caribou. (a) what are the frequencies of A_1 (p) and A_2 (q) in this small herd? Show your calculations. (b) What is the inbreeding coefficient F? Show the formula and your calculations (c) If coefficients of inbreeding in five large caribou herds that do not have calves with bone abnormalities are 0.22, 0.13, 0.30, 0.29, and 0.10, what should the researchers conclude about bone problems in their small group of caribou and why?

Explanation / Answer

Q.No 1

P2+2pq+q2 = 1

p2 = percentage of homozygous dominant individuals

q2 = percentage of homozygous recessive individuals

2pq = percentage of heterozygous individuals

A1 (2)= 8 ; A2(q) = 6

P2 = 64 ; q2 = 36; 2pq = 96

Q.No 2

Inbreeding coefficient

f = (½)n

Here, n= 24

f = (1/2)24 = 1/16777216

f= 5.96

Q.No 3

Nodes/Path = 5

f = (½)n + (½)n

   = (1/2)5 + (1/2)5

   = 0.031+0.031

   = 1/16

So the first progeny have small coefficient 1/16

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