Hey how would I solve this? The coil of wire in a galvanometer has a resistance

Question

Hey how would I solve this? The coil of wire in a galvanometer has a resistance ofRC = 52.0. The galvanometer exhibits afull-scale deflection when the current through it is 0.325 mA. Aresistor is connected in series with this combination so as toproduce a voltmeter. The voltmeter is to have a full-scaledeflection when it measures a potential difference of 17.7 V. Whatis the resistance of this resistor?
Thank you! Hey how would I solve this? The coil of wire in a galvanometer has a resistance ofRC = 52.0. The galvanometer exhibits afull-scale deflection when the current through it is 0.325 mA. Aresistor is connected in series with this combination so as toproduce a voltmeter. The voltmeter is to have a full-scaledeflection when it measures a potential difference of 17.7 V. Whatis the resistance of this resistor?
Thank you!

Explanation / Answer

This is confusing, but what they are trying to say is... .       the resistor is in series withthe coil, so total resistance is     52.0 +R . Using ohms law:       total voltage = total resistance * total current .          17.7 = (52.0 + R) * 0.325 x 10-3 . Solve forR...        R = 54409Ohms      . Solve forR...        R = 54409Ohms     

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