The angular momentum of a flywheel having a rotational inertia of0.250 kg·m 2 ab

Question

The angular momentum of a flywheel having a rotational inertia of0.250 kg·m2 about itscentral axis decreases from 2.40 to1.000 kg·m2/s in2.00 s.
(a) What is the magnitude of the average torque acting on theflywheel about its central axis during this period?   _____N*M
(b) Assuming a uniform angular acceleration, through whatangle does the flywheel turn? ___rad
(c) How much work is done on the wheel? _____J
(d) What is the average power of the flywheel? _____W
(a) What is the magnitude of the average torque acting on theflywheel about its central axis during this period?   _____N*M
(b) Assuming a uniform angular acceleration, through whatangle does the flywheel turn? ___rad
(c) How much work is done on the wheel? _____J
(d) What is the average power of the flywheel? _____W

Explanation / Answer

(a)     the average torque will be     avg = (Lf -Li) / t     where Li is the initial angularmomentum and Lf is the final angular momentum (b)     the angle turned will be     = o t + (1 / 2) t2     if the angular acceleration is uniformthen so is the torque and     = / I     o = Li / I and weobtain that     = Li t + (1 / 2) t2 / I        = ......... rad (c)     the work done on the wheel is     W =    = ....... J (d)     the average power will be     Pavg = - W / t            = ........ W

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