Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

P1) A compact car has a mass of 1200 kg. Assumethat the car has one spring on ea

ID: 1674644 • Letter: P

Question

P1) A compact car has a mass of 1200 kg. Assumethat the car has one spring on each wheel, that the springs are identical, and that the mass isequally distributed over the four springs. a. What is the spring constant of each spring ifthe empty car bounces up and down 2.0 times each second? b. What will be the car’s oscillationfrequency while carrying four 70. kg passengers?
the teacher didn't really explain this well in class so imkind of lost on this problem. any help would be appretiatied P1) A compact car has a mass of 1200 kg. Assumethat the car has one spring on each wheel, that the springs are identical, and that the mass isequally distributed over the four springs. a. What is the spring constant of each spring ifthe empty car bounces up and down 2.0 times each second? b. What will be the car’s oscillationfrequency while carrying four 70. kg passengers?
the teacher didn't really explain this well in class so imkind of lost on this problem. any help would be appretiatied

Explanation / Answer

   a.   Mass supported by eachspring      m   =   1200/ 4                                                                      =   300   kg       time period ofoscillation   T   =   2* (m / k)       given   T   =   1/ 2.0                                   =   0.5   s       =>   0.52   =   (2)2* 300 / k        springconstant   k   =   6.282* 300 / 0.25                                  =   4.733* 104   N/m    b.   Total mass of car withfourpassengers      M   =   1200+ 4 * 70.0                                                                               =   1480.0   kg          Masssupported by eachspring      m'   =   M/ 4                                                                      =   1480.0 /4                                                                      =   370.0   kg          New timeperiod   T '  =   2* (m' / k)                                           =   6.28* (370.0 / 4.733 * 104)                                           =   0.5553   s          newfrequency   F   =   1/ T '                                              =   1/ 0.5553                                              =   1.80   s