A jellyfish is floating in a water-filled aquarium 0.21 m behind a flat pane of
ID: 1674704 • Letter: A
Question
A jellyfish is floating in a water-filled aquarium 0.21 m behind a flat pane of glass 1.00 cm thick and having an index of refraction of1.52. (a) Where is the image of thejellyfish located? (Use a negative number to indicate the image isin the tank. Measure the distance from the air-glassinterface.)1 m
(b) Repeat the problem when the glass is so thin that its thicknesscan be neglected. (Use a negative number to indicate the image isin the tank.)
2 m
(c) How does the thickness of the glass affect the answer to part(a)?
thickness has no effect on the answer topart (a)
the thicker the glass, the greater thedistance between the final image and the outer surface of theglass
the thinner the glass, the greater thedistance between the final image and the outer surface of theglass
Explanation / Answer
n1 sin 1 = n2 sin2 = n3 sin 3 1 is the angle subtended by two close pointson the jelly fish (from a line perpendicular to the glass) 2 is the same for the angles ofrefraction and incidence inside the glass 3 is the angle outside the glassperceived by the eye sin 1 / sin 3 =n3 / n1 = n3 =1.33 since n1 is 1 forair (n3 = 1.33 forwater) 1 / 3 =1.33 the magnification since is very smallfor 2 close points on the jelly fish (The eye assembles an image from sets of closely spacedpoints) 1 / 3 = H / h where H is the height of the image perceived by the eye for twopoints separated by h on the jelly fish So the object will appear 1.33 times closer than it's actualdistance For the thick glass the apparent distance is .22 / 1.33 = .165m For the thin glass the apparent distance is .21 / 1.33 = .158m 1 is the angle subtended by two close pointson the jelly fish (from a line perpendicular to the glass) 2 is the same for the angles ofrefraction and incidence inside the glass 3 is the angle outside the glassperceived by the eye sin 1 / sin 3 =n3 / n1 = n3 =1.33 since n1 is 1 forair (n3 = 1.33 forwater) 1 / 3 =1.33 the magnification since is very smallfor 2 close points on the jelly fish (The eye assembles an image from sets of closely spacedpoints) 1 / 3 = H / h where H is the height of the image perceived by the eye for twopoints separated by h on the jelly fish So the object will appear 1.33 times closer than it's actualdistance For the thick glass the apparent distance is .22 / 1.33 = .165m For the thin glass the apparent distance is .21 / 1.33 = .158mRelated Questions
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