Pendulum string length L attached to a ball. Pendulum\'sstring is stopped by a p

Question

Pendulum string length L attached to a ball. Pendulum'sstring is stopped by a peg when the ball attached to string swingsleft, but moves freely when the ball moves to the right. Note: When peg stops string, the distance from peg toball is "J"
Questions: Is the period of this pendulum greater than, less than or sameas the period of the same pendulum without the peg?
Calculate the period of the pendulum in terms of L and J
Evaluate the result for L=1.3m and J=0.20m
Questions: Is the period of this pendulum greater than, less than or sameas the period of the same pendulum without the peg?
Calculate the period of the pendulum in terms of L and J
Evaluate the result for L=1.3m and J=0.20m

Explanation / Answer

a. The period of this pendulum is less than the period of the same pendulum without the peg.

b. T = pi seqrt L/g + pi seqrt l/g

c. T= 3.14 ? 1.3/9.8 + 3.14 ?.20/9.8 = 1.59

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.