A permanent bar magnet has a field strength of 1T. Suppose wehave a circular wir

Question

A permanent bar magnet has a field strength of 1T. Suppose wehave a circular wire loop of radius R=0.50 cm that is carrying acurrent of I Amperes. What current is required to make a magneticfield at the center of the wire loop that is equal to the field ofthe bar magnet? Any help is greatly appreciated, will rate quickly. A permanent bar magnet has a field strength of 1T. Suppose wehave a circular wire loop of radius R=0.50 cm that is carrying acurrent of I Amperes. What current is required to make a magneticfield at the center of the wire loop that is equal to the field ofthe bar magnet? Any help is greatly appreciated, will rate quickly.

Explanation / Answer

The maximum value of the field is at x = 0,the center of theloop or coil:
Bx = (oNI/2R) (at the center of Ncircular loops)
As we go out along the axis,the field decreases in magnitude. The current required to make a magnetic field at the center ofthe wire loop that is equal to the field of the bar magnet is I = (Bx * 2R/oN) where Bx = 1 T,R = 0.50 cm = 0.50 * 10-2m,o= 4 * 10-7 Wb/A.m and N =1

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