I\'ve tried this over and over again, but it says that myanswer is wrong. Here i

Question

I've tried this over and over again, but it says that myanswer is wrong. Here is the problem: A 1.40- resistor is connected across a9.00-V battery. The voltage between the terminals of the battery isobserved to be only 8.10 V. Find the internal resistance of thebattery.
Thanks! I've tried this over and over again, but it says that myanswer is wrong. Here is the problem: A 1.40- resistor is connected across a9.00-V battery. The voltage between the terminals of the battery isobserved to be only 8.10 V. Find the internal resistance of thebattery.
Thanks!

Explanation / Answer

A Resistor   R = 1.40 , is connected across the battery   =9.00 V             According to Ohm's law I = V / R                                                       = 9.00 V / 1.40                                                        = 6.42 A Voltage between the terminals is Vab = - I r                                                                                                             8.10 V = 9.00 V - 6.42 A ( r )                               Internal resistance r = 0.140

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