what is the solution to these problems? The dome of a Van de Graaff generator re
ID: 1675371 • Letter: W
Question
what is the solution to these problems? The dome of a Van de Graaff generator receives a charge of5.0 X 10-4 C. Find thestrength of the electric field in the following situations. (Hint:See Section 15.6 to review properties of conductors inelectrostatic equilibrium. Also use the fact that the points on thesurface are outside a spherically symmetric charge distribution;the total charge may be considered as located at the center of thesphere.) (a) inside the domeN/C
(b) at the surface of the dome, assuming it has a radius of3.0 m N/C
(c) 4.0 m from the center of thedome
N/C what is the solution to these problems? The dome of a Van de Graaff generator receives a charge of5.0 X 10-4 C. Find thestrength of the electric field in the following situations. (Hint:See Section 15.6 to review properties of conductors inelectrostatic equilibrium. Also use the fact that the points on thesurface are outside a spherically symmetric charge distribution;the total charge may be considered as located at the center of thesphere.) (a) inside the dome
N/C
(b) at the surface of the dome, assuming it has a radius of3.0 m N/C
(c) 4.0 m from the center of thedome
N/C (a) inside the dome
N/C
(b) at the surface of the dome, assuming it has a radius of3.0 m N/C
(c) 4.0 m from the center of thedome
N/C
Explanation / Answer
a. Electric field insidethe dome E = 0 As allthe charge resides on the surface. b. At thesurface E3.0 = (1/40)* q / R2= 9.0* 109 * 5.0 * 10-4 / 3.02 = 5.0* 105 N/C c. At r = 4.0 m E4.0 = (1/40)* q / r2 = 9.0* 109 / 5.0 * 10-4 / 4.02 = 2.81* 105 N/C = 2.81* 105 N/C
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.