In Figure below, an electron accelerated from rest throughpotential difference V

Question

In Figure below, an electron accelerated from rest throughpotential difference V1=1.07 kV enters thegap between two parallel plates having separation d= 26.1 mm and potentialdifference V2= 101 V. The lower plateis at the lower potential. Neglect fringing and assume that theelectron's velocity vector is perpendicular to the electric fieldvector between the plates. In unit-vector notation, what uniformmagnetic field allows the electron to travel in a straight line inthe gap?

Explanation / Answer

V1=1.07 (kV) d = 26.1 (mm) V2= 101 (V) we have qV1 = mv2/2 => v =(2qV1/m) E = V2/d E + v x B = 0 so, B = E/v    = V2/d *[m/(2qV1)        =1.99*10-4 T

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