An ideal gas occupies 0.262 m 3 at a gauge pressure of 332 kPa. Find the gauge p

Question

An ideal gas occupies 0.262 m3 at a gaugepressure of 332 kPa. Find the gauge pressure if the volumechanges to 0.377 L and the temperature remains constant.
Final gauge pressure in kPa? An ideal gas occupies 0.262 m3 at a gaugepressure of 332 kPa. Find the gauge pressure if the volumechanges to 0.377 L and the temperature remains constant.
Final gauge pressure in kPa? An ideal gas occupies 0.262 m3 at a gaugepressure of 332 kPa. Find the gauge pressure if the volumechanges to 0.377 L and the temperature remains constant.
Final gauge pressure in kPa?

Explanation / Answer

equation for ideal gas: PV=n*R*T P1*V1/T1=P2*V2/T2 P1=332kPa +105 Pa V1=262 L V2=0.377 L T1=T2 => P2=0.3*109 Pa => gauge pressure: P=P2-105=0.3*106 kPa

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