Can someone explain this problem to me when the length of thelonger wire is 4L?

Question

Can someone explain this problem to me when the length of thelonger wire is 4L?
This is what I have but it's incorrect:
length of shorter wire = L length of longer wire = 4L tension in the longer wire is four times greater than the shorter wire fundamental frequency in shorter wire is 70 Hz
f2 = 2f1    = 2(70 Hz)    = 140 Hz
This is what I have but it's incorrect:
length of shorter wire = L length of longer wire = 4L tension in the longer wire is four times greater than the shorter wire fundamental frequency in shorter wire is 70 Hz
f2 = 2f1    = 2(70 Hz)    = 140 Hz

Explanation / Answer

Length L = L

           L‘ = 4L

Tension T = T

            T ‘ = 4 T

Fundamental frequency of shorter wire f = 70 Hz

We know fundamental frequency f = ( 1/ 2L ) [ T/ m ]

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