Only a small part of an iceberg protrudes above the water,while the bulk lies be

Question

Only a small part of an iceberg protrudes above the water,while the bulk lies below the surface. The density of ice is907 kg/m3 and that ofseawater is 1029 kg/m3.Find the percentage of the iceberg's volume that lies below thesurface A solid, square pinewood raft measures 4.4 m on a side and is 3.00 m thick. What is the total mass of swimmersthat the raft can carry and float with its top surface at waterlevel? I'm really having trouble solving with ArchimedesPrinciple..Please help Only a small part of an iceberg protrudes above the water,while the bulk lies below the surface. The density of ice is907 kg/m3 and that ofseawater is 1029 kg/m3.Find the percentage of the iceberg's volume that lies below thesurface A solid, square pinewood raft measures 4.4 m on a side and is 3.00 m thick. What is the total mass of swimmersthat the raft can carry and float with its top surface at waterlevel? I'm really having trouble solving with ArchimedesPrinciple..Please help

Explanation / Answer

1>let x be the amount of volume that lies below thesurface,     according to Archimedes principle,     total weight of water displaced by thesolid=total weight of solid.    x*v*w*g=v*i *g [v=volume of solid, w=specific density of seawater,i=specific density of ice]     x*1029=907     x=907/1029=0.88144=88.14%   [Ans.] 2>   according to Archimedes principle,          totalweight of water displaced by the solid=total weight of solid.         v*w*g=v`*s*g      [v=vol. of square raft only, v`=vol. of square raft+increased volof raft due to swimmer, w=specific density ofwater, s=specific density of solid raft,] v*w=v`*s v`=v*w/s total mass ofswimmer=(v`-v)*s=v*(w/s-1)*s=v*(w-s)=4.4*4.4*3*(w-s)   [Ans.]

Related Questions

Navigate

• Browse (All)
• Browse O
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.