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Exactly 2.42 moles of an ideal gasundergoes an isothermal expansion (T = 304K) f

ID: 1676958 • Letter: E

Question

Exactly 2.42 moles of an ideal gasundergoes an isothermal expansion (T = 304K) from state A to state B and then returns to state A by anotherprocess. The volume of the gas in state B is three times itsinitial volume.
(a) For the process AB, find the work done bythe gas and its change in entropy.
work = ____________ J change in entropy = ________ J/K
(b) Find the gas's change in entropy for the process BA.
J/K
(a) For the process AB, find the work done bythe gas and its change in entropy.
work = ____________ J change in entropy = ________ J/K
(b) Find the gas's change in entropy for the process BA.
J/K work = ____________ J change in entropy = ________ J/K

Explanation / Answer

No.of moles n = 2.42 mol

Temp T = 304 K

Initila volume V = V

Final volume V ‘ = 3 V

Work done W = nRT ln ( V ‘ / V )

Where R = gas constant = 8.314 J / mol K

Plug the values we get W = 6719.6 J

Change in entropy dS = nR ln ( V ‘ / V )

                                  = 22.1 J / K

(b). Change in entropy dS ‘ = -dS = -22.1 J / K

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