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Electrons are accelerated from rest through a potentialdifference of V o and the

ID: 1677520 • Letter: E

Question

Electrons are accelerated from rest through a potentialdifference of Vo   and then pass through aregion between two parallel metal plates. The region betweenplates contains a uniform electric field E and uniform magneticfield B. With only electric field present electrons followpath 1. With only magnetic field present electrons followpath 3 . With both fields present electrons pass undeflectedalong straight path 2 a) Describe shape of the portion of path 1 betweenplates Justify your answer b) what is direction of electric field Explain c) Describe shape of portion of path 3 between plates. Justify your answer d) Between plates the magnitude of electric field is 3.4 x 104 V/m and magnitude of magnetic field is 2.0 x 10-3 T     Claculate speed ofelectrons given they are undeflected when both fields arepresent e) Calculate V o , potential difference,required to accelerate electrons to speed determined above Electrons are accelerated from rest through a potentialdifference of Vo and then pass through aregion between two parallel metal plates. The region betweenplates contains a uniform electric field E and uniform magneticfield B. With only electric field present electrons followpath 1. With only magnetic field present electrons followpath 3 . With both fields present electrons pass undeflectedalong straight path 2 a) Describe shape of the portion of path 1 betweenplates Justify your answer b) what is direction of electric field Explain c) Describe shape of portion of path 3 between plates. Justify your answer d) Between plates the magnitude of electric field is 3.4 x 104 V/m and magnitude of magnetic field is 2.0 x 10^-3 T Claculate speed ofelectrons given they are undeflected when both fields arepresent e) Calculate V o , potential difference,required to accelerate electrons to speed determined above

Explanation / Answer

Potential difference V= Vo

Initial speed u = 0

(a). shape of the portion of path 1 between plates isparabolic

b) The direction of electric field is from top plate tobottom plate

c) The shape of portion of path 3 between plates is circular

d) the magnitude of electric field B = 3.4 x 104 V/m

magnitude of magnetic field B = 2.0 x 10-3 T  

speed of electrons given they are undeflected when both fieldsare present is v = E / B

                                                                                                                             = 17*10^6 m / s

e) potential difference, required to accelerate electronsto speed determined above be V o

we know v = [ 2Voq / m]

where m = mass of electron = 9.11 * 10 ^ -31 kg

           q = charge of electron = 1.6 * 10 ^ -19 C

from above equation Vo = ( 1/ 2q) mv^ 2

plug the values we get Vo = 822.74 Volt

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