A crate of fruit with a mass of 31.0kg and aspecific heat capacity of 3800 J/(kg

Question

A crate of fruit with a mass of 31.0kg and aspecific heat capacity of 3800 J/(kg*K) slides 8.80 m down aramp inclined at an angle of 37.5 degrees below thehorizontal.
If the crate was at rest at the top of the incline and has a speedof 2.75m/s at the bottom, how much work W1 on the crate byfriction?
Use 9.81 m/s^2 for the acceleration due to gravity and express youranswer in joules. A crate of fruit with a mass of 31.0kg and aspecific heat capacity of 3800 J/(kg*K) slides 8.80 m down aramp inclined at an angle of 37.5 degrees below thehorizontal.
If the crate was at rest at the top of the incline and has a speedof 2.75m/s at the bottom, how much work W1 on the crate byfriction?
Use 9.81 m/s^2 for the acceleration due to gravity and express youranswer in joules.

Explanation / Answer

work done by gravity = mgh = 31* 9.80 * 8.8 sin37.5 = 1627.49 Joules . final KE = (1/2) m v2 = (1/2) * 31* 2.752 =   117.22Joules . work energy theorem:    final KE = work done by gravity + work by friction .                  117.22 =   1627.49 + work byfriction

work by friction = - 1510.27 Joules

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.