A paralel plate Capacitor has a plate area 1 m 2 andthe diastance between plates

Question

A paralel plate Capacitor has a plate area 1 m2 andthe diastance between plates is 1 cm. a) Calculate the capacitance. b) What charge will the capacitor hold if the voltagedifference between its plates is 1000 V? c) Calculate the force a particle with charge q=10-10 C will feel when inside the capacitor charged at1000 V? A paralel plate Capacitor has a plate area 1 m2 andthe diastance between plates is 1 cm. a) Calculate the capacitance. b) What charge will the capacitor hold if the voltagedifference between its plates is 1000 V? c) Calculate the force a particle with charge q=10-10 C will feel when inside the capacitor charged at1000 V?

Explanation / Answer

a ) Area of a parallel plate Capacitor is A = 1 m2                   distance between the plates d = 1 cm                                                                   = 0.01 m          Capacitance of a Capacitor C   = 0A / d                                                              =8.85*10-12 * 1 m2 / 0.01 m                                                             = 0.885*10-9 F        b )   charge on the plates Q = C V                                                        =   0.885*10-9 F   * 1000 V                                                         = 0.885 *10-6 C c )      E    = k Q / r2                  = 9*109 *  0.885 *10-6C   / (0.01 m )2                   =79.65*106 N /C           F = q E              = 1 *10-10 C *  79.65*106 N/C              = 7.965*10-3 N

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