I cannot find the right answer to this problem, and my computer isnot letting me

Question

I cannot find the right answer to this problem, and my computer isnot letting me open the link to this problem in cramster. Hopefullysomeone can help me with this one.

InteractiveLearningWare 13.2 reviews the concepts that are involved inthis problem. Suppose the skin temperature of a naked person is35.7 °C when the person is standing inside a room whosetemperature is 25.1 °C. The skin area of the individual is 1.76m2. (a) Assuming the emissivity is0.516, find the net loss of radiant power from the body.(b) Determine the number of food Calories ofenergy (1 food Calorie = 4186 J) that is lost in 9.07 hours due tothe net loss rate obtained in part (a). Metabolicconversion of food into energy replaces this loss.

Explanation / Answer

(a) net loss of power = A e(T24   -    T14 ) =
.    = 5.6696x  10-8  * 1.76 * 0.516 *( 308.854 - 298.254) =   61.081Watts . (b) This is    61.081 Joules persecond. And we know   9.07 hours = 32652 seconds . So you have    61.081 * 32652 =    1994406 Joules radiated.   Thisis the same as .          1994406 / 4186   =     476.4 food calories

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