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Question

x.Hmellpadding="0" cellspacing="0" border="0"> Question Details: has a half-life of 30.8 If we have 8.7 initially, how many Cs nuclei are present? How many are present 2.0 later?

Explanation / Answer

Half life T = 30.8 s

Mass m = 8.7 * 10 ^ -6 g

Molecular mass M = 124 g

No.of moles n = m / M

                       =7.016* 10 ^ -8 mol

No.of atoms N = n* 6.023 * 10 ^ 23   Since 1mole contain 6.023 * 10 ^ 23 atoms

So, N = 4.22* 10 ^ 16

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