A 0.150-kg block of ice is placed against a horizontal, compressedspring mounted

Question

A 0.150-kg block of ice is placed against a horizontal, compressedspring mounted on a horizontal tabletop that is 1.20 m above thefloor. The spring has force constant 1900 N/m and is initiallycompressed 0.045 m. The mass of the spring is negligible. Thespring is released, and the block slides along the table, goes offthe edge, and travels to the floor. If there is negligible frictionbetween the block of ice and the tabletop, what is the speed of theblock of ice when it reaches the floor? Searching updates...1/14
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Explanation / Answer

the speed of the block of ice when it reaches the flooris v by using the conservation of energy: potential energy of the spring + gravity potential of theblock=final kinetic energy k*0.0452/2+mg*1.2=m*v2/2 v=7.012m/s

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