A 0.84 kg block is attached to a spring andallowed to oscillate. The displacemen
ID: 1679035 • Letter: A
Question
A 0.84 kg block is attached to a spring andallowed to oscillate. The displacement from equilibrium as afunction of time is given by: x = (10 cm) cos (2 rad/s t + ) a) Find the maximum kinetic energy. b)Find the maximum force exerted by the spring. c)Find the displacement when the velocity is ¼ of itsmaximum. A 0.84 kg block is attached to a spring andallowed to oscillate. The displacement from equilibrium as afunction of time is given by: x = (10 cm) cos (2 rad/s t + ) a) Find the maximum kinetic energy. b)Find the maximum force exerted by the spring. c)Find the displacement when the velocity is ¼ of itsmaximum. c)Find the displacement when the velocity is ¼ of itsmaximum.Explanation / Answer
Mass m = 0.84 kg
The displacement from equilibrium as a function of time isx = (10 cm) cos (2 rad/s t + )
Compare this with x = A cos ( wt + )
We get amplitude A= 10 cm =0.1 m
Angular frequency w= 2 rad / s
a) the maximum kinetic energy K = ( 1/ 2) mw^ 2 A ^ 2
= 0.0168 J
b)the maximum force exerted by the spring F max = KA
= mw^ 2 * A
= 0.336 N
velocity v = V max / 4
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