A 950 kg car is pullinga 295 kg trailer. Together,the car and trailer have an ac

Question

A 950 kg car is pullinga 295 kg trailer. Together,the car and trailer have an acceleration of 2.24 m/s2 in the forwarddirection. Neglecting frictional forces on the trailer, determinethe following (including sign). (a) the net force on the car
N

(b) the net force on the trailer
N

(c) the force exerted by the trailer on the car
N

(d) the resultant force exerted by the car on the road magnitude N direction °(counterclockwise from the positive x axis)

(a) the net force on the car
N

(b) the net force on the trailer
N

(c) the force exerted by the trailer on the car
N

(d) the resultant force exerted by the car on the road magnitude N direction °(counterclockwise from the positive x axis)

magnitude N direction °(counterclockwise from the positive x axis)

Explanation / Answer

(a) the net force on the car
The total force on the car Ft is Ft= (m1 + m2)a
Ft= (950 + 295) 2.24 = Ft= 2790 N By net force they mean the the force applied to the car less the trailer Then F net car = m1a = 950 x 2.24   = F net car =  2130 N

(b) the net force on the trailer

F1= m2a F1= 295 x 2.24= 660 N

(c) the force exerted by the trailer on the car

action force is equal to reaction force F1= 295 x 2.24= 660 N

(d) the resultant force exerted by the car on the road

We have two forces to consider, the normal to the surface force N ( weight of the car) and tangential force T (force acted upon the road by the car) F = sqrt ( T2 + N2) = F= sqrt( Ft 2 + (m1g )2 ) where m1g = 950 x 9.8 =9310 N F= sqrt ( 2790 2 + (9310)2 ) F= 9720 N angle= arctan( N/T)

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