The work function for indium is4.12 eV. (a) Convert the value of the work functi
ID: 1679346 • Letter: T
Question
The work function for indium is4.12 eV. (a) Convert the value of the work function fromelectron volts to joules.1 J
(b) Find the cutoff frequency for indium.
2 Hz
(c) What maximum wavelength of light incident on indium releases photoelectrons from the indium's surface?
3 m
(d) If light of energy 8.6 eV is incidenton indium, what is the maximum kineticenergy of the ejected photoelectrons? Give the answer in electronvolts.
4 eV
(e) For photons of energy 8.6 eV, whatstopping potential would be required to arrest the current ofphotoelectrons?
5 V (a) Convert the value of the work function fromelectron volts to joules.
1 J
(b) Find the cutoff frequency for indium.
2 Hz
(c) What maximum wavelength of light incident on indium releases photoelectrons from the indium's surface?
3 m
(d) If light of energy 8.6 eV is incidenton indium, what is the maximum kineticenergy of the ejected photoelectrons? Give the answer in electronvolts.
4 eV
(e) For photons of energy 8.6 eV, whatstopping potential would be required to arrest the current ofphotoelectrons?
5 V
Explanation / Answer
Work function W = 4.12 eV
(a). W = 4.12 eV = 4.12 * 1.6* 10 ^ -19 J
= 6.592 *10 ^ -19 J
(b). Cut off frequency f = W / h
Where h = planck’s constant = 6.625 * 10 ^ -34J s
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