In the figure the four particles are fixed in place and havecharges q 1 = q 2 =3

Question

In the figure the four particles are fixed in place and havecharges q1 = q2 =3e,q3 =3e, and q4 =-11e. Distance d = 3.79m. What is the magnitude of the net electric field atpoint P due to the particles? Could someone help me with this one please? Thanks! In the figure the four particles are fixed in place and havecharges q1 = q2 =3e,q3 =3e, and q4 =-11e. Distance d = 3.79m. What is the magnitude of the net electric field atpoint P due to the particles? Could someone help me with this one please? Thanks!

Explanation / Answer

The net electric field at point P is given by       E = k( q1 /d2)+  k( q2 /d2) +  k( q3/d2) + k( q4 / (2d) 2)          =k/d2 [ q1 + q2 + q3 +( q4 / 4) ]                 =(9*109) / (3.79*10-6 )2 [ 3e+3e +3e +(-11e / 4) ]         =0.626*1021 (6.25*1.6*10-19 ) = 626N/C

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