A mountain climber, in the process of crossing between two cliff s by a rope, pa

Question

A mountain climber, in the process of crossing between two cliffs by a rope, pauses to rest. She weighs 555 N.  she is closer to the left cliff than to 2 the right cliff, with the result that the tensions in the left and the right sides of the rope are not the same. Find the tensions in the rope to the left and to the right of the mountain climber. (Hint: Notice that the climber's and the rope's accelerations are zero! Carefully draw a free body diagram for the point on the rope above the climber and apply Newton's second law. You will need to consider both the x and the y axis to solve for both tensions.)

Explanation / Answer

let the angle made by the left rope and tension T1 IN THE RIGHT ROPE LET IT BE T2 AND hence from the equilibrium of the climber in horizontaldirection as T1cos=T2cos   i.ecos=T1cos/T2 and T1sin+T2sin=555N  sin=555-T1sin/T2 we have as cos2+sin2=1   we get sin in terms of T1 and T2 hence substituting in the basic equations deduced we have T1 andT2

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