A capacitor consistingof two concentric spheres of radius R 1 and R 2 = 2.50·R 1
ID: 1679842 • Letter: A
Question
A capacitor consistingof two concentric spheres of radius R1 and R2= 2.50·R1 has a capacitance of C = 6.00picoFarads and is charged to a potential difference of 82.0 Volts.Calculate the energy stored in the capacitor.Tries 0/10
Calculate the chargeon this capacitor, when the electrical energy stored is27.9·10-8 Joules.
Tries 0/10
If the radius of theouter sphere is increased by a factor of 4.50 while keeping thecharge on the plates constant, by what factor does the storedenergy change?
Tries 0/10 Tries 0/10
Explanation / Answer
Capacitance C = 6 * 10 ^ -12 F
Potential difference V = 82 V
Energy stored in the capacitor E = ( 1/ 2) C V^ 2
= 2.0172*10^-8 J
(b). electrical energy U = 27.9* 10 ^ -8 J
Capacitance C = 6 * 10 ^ -12 F
We know U = Q ^ 2/ 2C
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