Q#1 The charge (coul) on an object increases according to(q) =(2coul)e [(.050/se

Question

Q#1 The charge (coul) on an object increases according to(q) =(2coul)e [(.050/sec)(t)], where t is in seconds. At how manyseconds is the object deficient 1.56*10uppercase20 electron (fromneutral)/ (a) 0 (b)12.56 (c)21.94 (d)28.0 (e)41.21 (a,b)50.5 (a,c)65.90 (a,d)105.00 (a,e)874.00 (b,c)1000.00 Q#1 The charge (coul) on an object increases according to(q) =(2coul)e [(.050/sec)(t)], where t is in seconds. At how manyseconds is the object deficient 1.56*10uppercase20 electron (fromneutral)/ (a) 0 (b)12.56 (c)21.94 (d)28.0 (e)41.21 (a,b)50.5 (a,c)65.90 (a,d)105.00 (a,e)874.00 (b,c)1000.00

Explanation / Answer

1 e = 1.60 x 10-19 C Q = 1.56 x 1020 e = 25.0 C Q = (2C)exp[0.050s-1t] 25.0 C = (2C)exp[0.050s-1t] ln(12.5) = 0.050s-1t t = 0.050-1ln(12.5)s t = 50.5 s

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