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A 1.0-F and a 2.0-Fcapacitor are connected in series across a 3.0-V battery. Wha

ID: 1680173 • Letter: A

Question

A 1.0-F and a 2.0-Fcapacitor are connected in series across a 3.0-V battery. What isthe voltage across the 1.0-F capacitor?




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Solution is not 4.5, answer choices are 1.0V, 2.0V, 3.0V, or0V
The solution below, I believe, forgot to take the reciprocalof Ceq. It should be 1/1.5F= .66667
      then, Q= (.6667)(3.0V)= 2C ------>V = 2.0C/1F= 2V <---this is mysolution
Am I correct?




Will rate for complete answers! Thanks!
Solution is not 4.5, answer choices are 1.0V, 2.0V, 3.0V, or0V
The solution below, I believe, forgot to take the reciprocalof Ceq. It should be 1/1.5F= .66667
      then, Q= (.6667)(3.0V)= 2C ------>V = 2.0C/1F= 2V <---this is mysolution
Am I correct?

Explanation / Answer

Since the capacitors are in series, the netcapacitance=C1C2/(C1+C2)                 =1*2/(1+2)                 =2/3F                 =0.66F Remember, when the capacitors are in series, the charge(q) isconstant. we know that q=CTV                        =0.66*3                       =2C Therefore, using q=CV for the 1 capacitor, 2=1*V V=2V you are correct.