a home run is hit in such a way that the baseball just clears awall 21.0m high,

Question

a home run is hit in such a way that the baseball just clears awall 21.0m high, located 130m from home plate. The ball is hit at aheight of 1.00m above the ground at an angle of 35 degrees to thehorizontal, and air resistance is negligible. The initial speed ofthe ball was?

Explanation / Answer

The horizontal distance X = v t = v cos35 * t      ==> v * t = 130 / cos35 = 158.700 The vertical distance of the ball in time t is       y = v sin35 * t -0.5gt2      21 = v sin35 * t -0.5gt2      21 = 91.0- 4.9 t2     4.9t2 = 70     ==> t = 3.779 s from above we have         v * t = 158.7 ==> v = 41.98 m/s

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