A toy cannon uses a spring to project a 5.80g projectile. The spring is original
ID: 1680610 • Letter: A
Question
A toy cannon uses a spring to project a 5.80g projectile. The spring is originally compressed by 8.00cm and has a force constant of 15.54 N/m. When the spring is released, the projectile slides 15.0cm through the barrel of the cannon where the barrel exerts a constant fictional force on the projectile. The projectile leaves the barrel of the cannon with a speed of 3.50m/s. The barrel of the cannon makes a 60 degree angle with respect to the horizontal surface. Neglect any air resistance or any rotational effects. Assume that the projectile's starting elevation is at ground level. What is the force of kinetic friction between the projectile and the barrel of the cannon? What is the maximum height of the projectile above ground level during its flight? How long does it take the projectile to reach its height?Explanation / Answer
A toy cannon uses a spring to project a 5.80g projectile. Thespring is originally compressed by 8.00cm and has a force constantof 15.54 N/m. When the spring is released, the projectile slides15.0cm through the barrel of the cannon where the barrel exerts aconstant fictional force on the projectile. The projectile leavesthe barrel of the cannon with a speed of 3.50m/s. The barrel of thecannon makes a 60 degree angle with respect to the horizontalsurface. Neglect any air resistance or any rotational effects.Assume that the projectile's starting elevation is at ground level.What is the force of kinetic friction between the projectile andthe barrel of the cannon? work done=change in kinetic energy 1/2*15,54*0.08*0.08*k=1/2*0.0058*3.5*3.5 solving we will get coefficient of kinetic friction k according to work energy theorem What is the maximum height of the projectile above groundlevel during its flight? maximum height=3.5*3.5sin260/2*9.8=0.46875m How long does it take the projectile to reach its height? time= 3.5sin60/9.8==0.3092sec
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