The question is: A golf ball is hit off a tee at the edge of a cliff. It\'s x an

Question

The question is:
A golf ball is hit off a tee at the edge of a cliff. It's x and ycoordinates as functions of time are given below:
x=(18.0 m/s)t
y=(4.00 m/s)t+(4.9 m/s2)t2
a) Write a vector equation for the ball's position as a function oftime, using the unit vectors j^ and i^. Bytaking derivatives, obtain expressions for (b) the velocity vectora> as a function of time. Next use the unit-vectornotation to write expressions for (d) the position, (e) thevelocity, and (f) the acceleration of the gold ball, att=3.00s.

I think I'm figured out part a. I haver>f=(18 i^+4j^)t +(2.45 j^)t2, assuming that the initialposition of the golf ball was 0. Also, I know that the derivativeof position is velocity and the derivative of velocity isacceleration, but I'm not really sure where to go from here.
PS-I hope the symbols aren't too confusing!

Explanation / Answer

You're going to want to write it as r = (18t)i + (4t + 4.9t^2)j dr/dt = v = (18)i + (4+9.8t)j dv/dt = a = (9.8)j From there you can plug in 3 for t in all of those to figure outthe specifics.

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