A rubber ball is dropped and bounces vertically from ahorizontal concrete floor.

Question

A rubber ball is dropped and bounces vertically from ahorizontal concrete floor. If the ball has a speed of 3.2 m/s just before striking the floor and a speed of2.1 m/s just after bouncing, what is theaverage force of the floor on the ball? Assume the ball is incontact with the floor for 0.14 s and themass of the ball is 0.16 kg.
N
A rubber ball is dropped and bounces vertically from ahorizontal concrete floor. If the ball has a speed of 3.2 m/s just before striking the floor and a speed of2.1 m/s just after bouncing, what is theaverage force of the floor on the ball? Assume the ball is incontact with the floor for 0.14 s and themass of the ball is 0.16 kg.
N

Explanation / Answer

F = p / t = [mv(f) -mv(i)] / t = [(0.16kg)(2.1m/s) - (0.16kg)(3.2m/s)] / 0.14s = -1.257N So the force is 1.257 N downward.

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