Two capacitors, C 1 = 25 µF and C 2 =5.0 µF, are connected inparallel and charge

Question

Two capacitors, C1 = 25 µF and C2 =5.0 µF, are connected inparallel and charged with a 140 Vpower supply. (a) Calculate the total energy stored in twocapacitors.
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(b) What potential difference would be required across the same twocapacitors connected in series in order that the combination storethe same energy as in (a)?
-------------- V (a) Calculate the total energy stored in twocapacitors.
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(b) What potential difference would be required across the same twocapacitors connected in series in order that the combination storethe same energy as in (a)?
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Explanation / Answer

a )Two Capacitors are connected in series areC1  = 25F                                                                     C2 = 5.0F                                                              C' = C1 +C2                                                                     = 25+5.0                                                                     = 30.0 F              Energy stored in a Capacitor is E = 1/2CV2                                       Voltageacross the Capacitor V = 140 V                                                        E = 1 /2 * 30.0F * (140V)2                                                             = 0.294J b ) Capacitors connected in series C' =C1C2 / C1+C2                                                            = 25*5 / 25+5.0                                                            = 4.16F                                                           E = 1 /2 C V2                                                        0.294J = 1/2 * 4.16F * V2                                                           Voltage V = 0.375V

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