A 1.71 kg block and a 3.42 kg block are initially at rest on a frictionless,hori

Question

A 1.71 kg block and a 3.42 kg block are initially at rest on a frictionless,horizontal surface, with a compressed spring of negligible massbetween them. When the blocks are released, they move off inopposite directions. If the final velocity of the 1.71 kg block is 2.75 m/s tothe left, what is the final velocity of the 3.42 kg block?
magnitude 1 in what units direction 2
How much does the kinetic energy of the system increase?
In what units?
How much does the kinetic energy of the system increase?
In what units? magnitude 1 in what units direction 2

Explanation / Answer

m1u1 +m2u2 =m1v1 +m2v2 initial velocities are 0 (mass of spring is negligible so not taken inaccount) so v2 = -m1v1/m2 = 1.375 m/s to theright
KE increases by 1/2m1v12 + 1/2m2v22 = 3/4(1.71)(2.75)2 = 9.7 J initial velocities are 0 (mass of spring is negligible so not taken inaccount) so v2 = -m1v1/m2 = 1.375 m/s to theright
KE increases by 1/2m1v12 + 1/2m2v22 = 3/4(1.71)(2.75)2 = 9.7 J

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