Given a graph of Force vs. Position, where you have the forcefunction on the x-a

Question

Given a graph of Force vs. Position, where you have the forcefunction on the x-axis and the position function on the y-axis, theinitial position is 0.0 and then it increases linearly until itreaches 5.0meters where the force in (N) is about 12. So myquestion is: This graph is for the force exerted by a spring as afunction of distance it is stretched from its unstrechedlength.

a) What is the spring constant for this spring

b) What is the elastic PE if the spring is stretched 1.5 m from itsequilibrium length

c) A Low friction cart of mass 5.0kg is attached to the spring,when the spring is stretched 1.5 m from its equilibrium length andthen the cart is released what is the kinetic energy of the cartjust as the spring passes through its equilibrium length? What isthe velocity of the cart at this position?

Explanation / Answer

Force F=12N distance X=5m Spring constant K=F/X=12/5=2.4N/m2 -

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