A fireworks rocket is launched vertically into the night sky withan initial spee

Question

A fireworks rocket is launched vertically into the night sky withan initial speed of 41.4 m/s. The rocket coasts after beinglaunched, then explodes and breaks into two pieces of equal mass2.20s later.

Part 1)
If each piece follows a trajectory that is initially at 45.0degrees to the vertical, what was their speed immediately after theexplosion?

Part 2)
What is the velocity of the rocket's centerof mass before the explosion?

Part 3)
What is the acceleration of the rocket'scenter of mass before the explosion?

What is the velocity of the rocket's centerof mass before the explosion?

Part 3)
What is the acceleration of the rocket'scenter of mass before the explosion?
What is the acceleration of the rocket'scenter of mass before the explosion?

Explanation / Answer

----------------------- Initial momentum of the rocket = m v where m = mass of the rocket            v = initial velocity of the rocket = 41.4 m / s In vertical direction : -------------------- Initial momentum of the rocket = 0 After explosion of the rocket : ----------------------------- Horizonatl total momentum = ( m / 2 ) v 1sin 45 + ( m / 2) v 2 sin 45 Vertical total momentum =   ( m / 2 ) v1 cos 45 + ( m / 2) v 2 cos 45 equating initial and final momentum in both horizontal andvertical direction and solve them we get answers

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