____ N.m my answer was .5 N.m but it was counted as wrong, I don\'t knowif I cal
ID: 1681887 • Letter: #
Question
____ N.m
my answer was .5 N.m but it was counted as wrong, I don't knowif I calculated wrong or if the torque is meant to benegative. ____ N.m my answer was .5 N.m but it was counted as wrong, I don't knowif I calculated wrong or if the torque is meant to benegative. A hand crank is used to raise water from a well. The rope is woundaround a drum of radius R = 0.27 m and is under tension of 150 N directedvertically downward. A force F of magnitude 80 Nis applied to the handle at adistance r = 0.5 m from the center of the drum. F isperpendicular to r, as shown. What is the net torque about thecenter of the drum?
Explanation / Answer
First we need to find the torque from the water. = F*x = 150N * R w = 40.5 Nm because the direction isclockwise. Finding the torque of how much you push the crank with. = F*x = 80N * r c = 40.0N because counter-clockwisedirection. = c - w = -0.5 Nm This means that the bucket will continue downward. Hope thishelped! = -0.5 Nm This means that the bucket will continue downward. Hope thishelped!Related Questions
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