Fusion is the process by which the sun produces energy. One experimental techniq

Question

Fusion is the process by which the sun produces energy. One experimental technique for creating controlled fusion utilizes a solid-state laser that emits a wavelength of 1060 nm and can produce a power of 1.0 x 10^14 W for a pulse duration of 1.1 x  10^(-11)  s. In contrast, the helium/neon laser used at the checkout counter in a bar-code scanner emits a wavelength of 633 nm and produces a power of about 1.0 x 10^(-3) W. How long (in days) would the helium/neon laser have to operate to produce the same number of photons that the solid-state laser produces in 1.1 x  10^(-11)  s?

Explanation / Answer

E = N h f      energy of Nphotons P = E / t        definitionof power P1 = N1 h f1 /t1     power of solid statelaser P2 = N2 h f2 /t2     power of helium/neonlaser t2 / t1 = N2 f2P1 / (N1 f1P2)     dividing equations t2 / t1 = f2P1 / ( f1P2)       sinceN1 = N2 t2 =( P1 1 /P2 2) t1   since f = c / t2 = (1 * 10E14 * 1060 / (1 * 10E-3 * 633) *1.1 * 10E-11 = 1.8 * 10E6 sec 1 day = 3600 * 24 = 8.64 *10E4 sec time (days) = 1.8 * 10E6 / 8.64 *10E4 = 21 days t2 =( P1 1 /P2 2) t1   since f = c / t2 = (1 * 10E14 * 1060 / (1 * 10E-3 * 633) *1.1 * 10E-11 = 1.8 * 10E6 sec 1 day = 3600 * 24 = 8.64 *10E4 sec time (days) = 1.8 * 10E6 / 8.64 *10E4 = 21 days

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