Three point charges are located at the following points: -3 C at (x= 0.5m, y= 0m

Question

Three point charges are located at the following points: -3 C at (x= 0.5m, y= 0m) 6 C at (x= 0m, y= 0.5m) 4 C at (x= 0.5m, y= 0.5m)
Find the electric field vector at the origin.
Now, I've tried this a few times, and my answer hasn't matchedwhat it's supposed to be.. can anyone help me out on this one?Thanks a lot. -3 C at (x= 0.5m, y= 0m) 6 C at (x= 0m, y= 0.5m) 4 C at (x= 0.5m, y= 0.5m)
Find the electric field vector at the origin.
Now, I've tried this a few times, and my answer hasn't matchedwhat it's supposed to be.. can anyone help me out on this one?Thanks a lot.

Explanation / Answer

Given q = -3* 10^ -6 C          q ' = 6 * 10^ -6 C          q " = 4 * 10^-6 C electric field at orgin due to charge q is E = Kq/ x^ 2 where K = coulomb's constant = 8.99 * 10 ^ 9 Nm^ 2/ C ^2            x = distance of the origin from charge q = 0.5 m plug the values we get E = 107880 N / C It is along positive x - direction electric field at orgin due to charge q ' is E ' = Kq ' / y^ 2 where K = coulomb's constant = 8.99 * 10 ^ 9 Nm^ 2/ C ^2             y= distance of the origin from charge q = 0.5 m plug the values we get E' = 107880 N / C It is along negative y - direction x - component of electric field at orgin due to charge q" is E " = Kq" / x^ 2 where K = coulomb's constant = 8.99 * 10 ^ 9 Nm^ 2/ C ^2            x = distance of the origin from charge q = 0.5 m plug the values we get E" = 107880 N / C It is along negative x - direction y- component of electric field at orgin due to charge qis E "'= Kq" / y^ 2 where K = coulomb's constant = 8.99 * 10 ^ 9 Nm^ 2/ C ^2             y= distance of the origin from charge q = 0.5 m plug the values we get E "'= 107880 N / C It is along negative y - direction net electric field in x - direction e = E + ( -E ") = 0 net electric field in y - direction e ' = - ( E ' + E "' )                                                     = -215760 N / C electric field vector at origin = e i + e ' j                                           = 0 i -215760 j where i , j are unit vectors in positive x and ydirections respectively electric field at orgin due to charge q ' is E ' = Kq ' / y^ 2 where K = coulomb's constant = 8.99 * 10 ^ 9 Nm^ 2/ C ^2             y= distance of the origin from charge q = 0.5 m plug the values we get E' = 107880 N / C It is along negative y - direction x - component of electric field at orgin due to charge q" is E " = Kq" / x^ 2 where K = coulomb's constant = 8.99 * 10 ^ 9 Nm^ 2/ C ^2            x = distance of the origin from charge q = 0.5 m plug the values we get E" = 107880 N / C It is along negative x - direction y- component of electric field at orgin due to charge qis E "'= Kq" / y^ 2 where K = coulomb's constant = 8.99 * 10 ^ 9 Nm^ 2/ C ^2             y= distance of the origin from charge q = 0.5 m plug the values we get E "'= 107880 N / C It is along negative y - direction net electric field in x - direction e = E + ( -E ") = 0 net electric field in y - direction e ' = - ( E ' + E "' )                                                     = -215760 N / C electric field vector at origin = e i + e ' j                                           = 0 i -215760 j where i , j are unit vectors in positive x and ydirections respectively x - component of electric field at orgin due to charge q" is E " = Kq" / x^ 2 where K = coulomb's constant = 8.99 * 10 ^ 9 Nm^ 2/ C ^2            x = distance of the origin from charge q = 0.5 m plug the values we get E" = 107880 N / C It is along negative x - direction y- component of electric field at orgin due to charge qis E "'= Kq" / y^ 2 where K = coulomb's constant = 8.99 * 10 ^ 9 Nm^ 2/ C ^2             y= distance of the origin from charge q = 0.5 m plug the values we get E "'= 107880 N / C It is along negative y - direction net electric field in x - direction e = E + ( -E ") = 0 net electric field in y - direction e ' = - ( E ' + E "' )                                                     = -215760 N / C electric field vector at origin = e i + e ' j                                           = 0 i -215760 j where i , j are unit vectors in positive x and ydirections respectively y- component of electric field at orgin due to charge qis E "'= Kq" / y^ 2 where K = coulomb's constant = 8.99 * 10 ^ 9 Nm^ 2/ C ^2             y= distance of the origin from charge q = 0.5 m plug the values we get E "'= 107880 N / C It is along negative y - direction net electric field in x - direction e = E + ( -E ") = 0 net electric field in y - direction e ' = - ( E ' + E "' )                                                     = -215760 N / C electric field vector at origin = e i + e ' j                                           = 0 i -215760 j where i , j are unit vectors in positive x and ydirections respectively

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