An obese 2000 kg waterbuffalo climbs a hill at a 45 degreeangle. It manges to ma

Question

An obese 2000 kg waterbuffalo climbs a hill at a 45 degreeangle. It manges to make it 200 meters in 25 minutes. How much power was used during the ascent? How much potential energy did the rotund mamal gain? How much kinetic engergy was lost? An obese 2000 kg waterbuffalo climbs a hill at a 45 degreeangle. It manges to make it 200 meters in 25 minutes. How much power was used during the ascent? How much power was used during the ascent? How much potential energy did the rotund mamal gain? How much kinetic engergy was lost?

Explanation / Answer

mass m = 2000 kg angle = 45 degrees distance travelled in 25 min is S = 200 m time t= 25 min = 25 * 60 s = 1500 s height from ground corresponding to distance S along theincline h = S * sin            h = 141.42 m (a). power of ascent P = mgh / t                                    = 1847.9 W (b).Potential energy gain U = mgh                                          = 2771858.58 J (c).kinetic energy lost = potential energy gain  Since from law of conservation of energy                                  = 2771858.58 J (c).kinetic energy lost = potential energy gain  Since from law of conservation of energy                                  = 2771858.58 J

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.