Protons carry an electric charge of e=1.60x10 -19 C,electrons carry charge of -e

Question

Protons carry an electric charge of e=1.60x10-19C,electrons carry charge of -e, and neutrons are electricallyneutral. Protons and neutrons have a mass of 1.67x10-27kg, and electrons havea mass of 9.11x10-31 kg. Auniform electric field can exert a force on a charged particle thateffectively neutralizes the force of gravity on the particle,causing it to be "weightless". What is the strength of the electricfield that will levitate (a) a proton? (b) an electron? (c) analpha particle (two protons and two neutrons)? I know the answer to each part will be in N/C. E=F/q. And Ibelieve q=1.60x10-19C. In order to find the strength ofthe field I need to find the force, F. F=ma from Newton's SecondLaw. I don't have acceleration, so I was wondering how do I findacceleration for this specific problem? Protons carry an electric charge of e=1.60x10-19C,electrons carry charge of -e, and neutrons are electricallyneutral. Protons and neutrons have a mass of 1.67x10-27kg, and electrons havea mass of 9.11x10-31 kg. Auniform electric field can exert a force on a charged particle thateffectively neutralizes the force of gravity on the particle,causing it to be "weightless". What is the strength of the electricfield that will levitate (a) a proton? (b) an electron? (c) analpha particle (two protons and two neutrons)? I know the answer to each part will be in N/C. E=F/q. And Ibelieve q=1.60x10-19C. In order to find the strength ofthe field I need to find the force, F. F=ma from Newton's SecondLaw. I don't have acceleration, so I was wondering how do I findacceleration for this specific problem?

Explanation / Answer

No need to calculate acceleration. Just follow the proceduregiven below.    We know that               F = Eq       Given that force on a chargedparticle that effectively neutralizes the force of gravity on theparticle         i.e. F = mg Therefore            mg = Eq ==>     E = m g / q I hope this helps you.

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