Vector A has a magnitude of 8.60 units and makes an angle of 39.5° counter-clock

Question

Vector A has a magnitude of 8.60 units and makes an angle of 39.5° counter-clockwise from the positive x-axis. Vector B has a magnitude of 8.00 units and is directed along the negative x-axis.

(a) Using graphical methods, find the vector sum A + B .

Magnitude of A + B :____________units
Direction of A + B :______________° counterclockwise from +x-axis

(b) Using graphical methods, find the vector difference A -B .
Magnitude of A - B :_______________units
Direction of A - B:________________° counterclockwise from +x-axis

Explanation / Answer

A=8.6 cos 39.5 i + 8.6 sin 39.5 j=6.636 i + 5.47j B= -8i A+B=6.636 i + 5.47j -8i= -1.364i + 5.47j Direction: It lies in the second quadrant. Angle is [180-tan-1(5.47/1.364)]=104 counterclockwise from +x axis. A-B=6.636 i + 5.47j+8i=14.636i + 5.47j It lies in the first quadrant Angle is tan-1(5.47/14.636)=20.49 deg with +x axis

Related Questions

Navigate

• Browse (All)
• Browse V
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.