A 1.00 kg aluminum block and a 7.00 kg copper block are connected by a light str

Question

A 1.00 kg aluminum block and a 7.00 kg copper block are connected by a light string over a frictionless pulley. The two blocks are allowed to move on a fixed steel block wedge (of angle ? = 35.0°) as shown in the figure below.

Making use of the table below, determine the following.
(a) the acceleration of the two blocks
____________________. m/s2

(b) the tension in the string
_______________________.N

Coefficients of Frictiona µs µk
Steel on steel 0.74 0.57
Aluminum on steel 0.61 0.47
Copper on steel 0.53 0.36
Rubber on concrete 1.0 0.8
Wood on wood 0.25-0.5 0.2
Glass on glass 0.94 0.4
Waxed wood on wet snow 0.14 0.1
Waxed wood on dry snow - 0.04
Metal on metal (lubricated) 0.15 0.06
Ice on ice 0.1 0.03
Teflon on Teflon 0.04 0.04
Synovial joints in humans 0.01 0.003
a All values are approximate.

Explanation / Answer

____________________. m/s2 as the diagram is not included I assume that both the blocks are on the wedge
let us assume that 7kg block moves down and hence the acceleration of the system 7*9.8*sin35-µ1*7*9.8*cos35-1*9.8*sin35-µ2*1*9.8cos35=(7+1)*a where a is the acceleration of the system and µ1 is the coefficient of friction between copper and steel and µ2 is coefficient of friction between aluminium and steel =0.36 and 0.47 solve for it
_______________________.N T= 1*9.8*sin35+µ2*1*9.8cos35+1*a solve

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.