The flash unit in a camera uses a special circuit to “step up” the 3.4 V from th

Question

The flash unit in a camera uses a special circuit to “step up” the 3.4 V from the batteries to 300 V , which charges a capacitor The capacitor is then discharged through a flashlamp. The discharge takes 10 µs, and the average power dissipated in the flashlamp is 11 W. What is the capacitance of the capacitor? C= ?? F I tried 2.4 x 10^3 but that was not right The flash unit in a camera uses a special circuit to “step up” the 3.4 V from the batteries to 300 V , which charges a capacitor The capacitor is then discharged through a flashlamp. The discharge takes 10 µs, and the average power dissipated in the flashlamp is 11 W. What is the capacitance of the capacitor? C= ?? F I tried 2.4 x 10^3 but that was not right

Explanation / Answer

Pt = E = 1/2 CV2 .00011 J = 1/2 (C)(3002)
C = 2.4E-9 F

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